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Posted by Richard Crowley on 08/28/07 21:33
"Rick Merrill" wrote ...
> Richard Crowley wrote:
>> "Rick Merrill" wrote ...
>>> If you Could put them in series (presently in parallel) then
>>> the change would be 2x/(1/2).
>>
>> The formula for calculating series resistance is simply
>> to add them together. Rseries = Ra + Rb
>> For parallel it is: Rparallel = 1/(1/Ra + 1/Rb)
>>
>
> Hit enter too fast there?-)
>
> in this case Ra = Rb.
> So the ratio of series/parallel = 2Ra/(1/(1/Ra+1/Ra))
> or 2Ra*(2/Ra)
> or 4
>
> Sorry, I don't have a URL for algebra :-)
>
>
>> http://physics.bu.edu/py106/notes/Circuits.html
Dunno what point you are trying to make, but I think
I will stick with the formulae we've been using for
over 150 years. They actually work in real-world
circuits.
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