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Posted by Rick Merrill on 08/29/07 01:35
Richard Crowley wrote:
> "Rick Merrill" wrote ...
>> Richard Crowley wrote:
>>> "Rick Merrill" wrote ...
>>>> If you Could put them in series (presently in parallel) then
>>>> the change would be 2x/(1/2).
>>> The formula for calculating series resistance is simply
>>> to add them together. Rseries = Ra + Rb
>>> For parallel it is: Rparallel = 1/(1/Ra + 1/Rb)
>>>
>> Hit enter too fast there?-)
>>
>> in this case Ra = Rb.
>> So the ratio of series/parallel = 2Ra/(1/(1/Ra+1/Ra))
>> or 2Ra*(2/Ra)
>> or 4
>>
>> Sorry, I don't have a URL for algebra :-)
>>
>>
>>> http://physics.bu.edu/py106/notes/Circuits.html
>
> Dunno what point you are trying to make, but I think
> I will stick with the formulae we've been using for
> over 150 years. They actually work in real-world
> circuits.
>
>
So go try the experiment with two resistors and your multi-meter.
You Do have a multimeter don't you?
Thanks for the chuckle.
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