Posted by Jeff Rife on 04/18/06 01:30

Gene E. Bloch (spamfree@nobody.invalid) wrote in alt.tv.tech.hdtv:
> Two complete progressive scans, at 1/60 second each, equals 33 msec by
> *my* math. Please show me how a 15 ms response time equates to two
> complete progressive scans by *your* math.

Who cares about two complete scans? By the time the second scan is
starting, *none** of the pixels have finished changing from the first scan.
Thus, *every* pixel gets changed again before it finishes changing for
the first time.

In addition, some manufacturers fudge their specs (say it isn't so!) so
that an LCD rated at 15ms can only achieve that in very specific
circumstances (usually white to black or black to white). Other changes
can require more time...sometimes as much as twice as long. If that's
the case, then some pixels will get *two* new change requests before it
finishes changing for the first time.

--
Jeff Rife |
| http://www.nabs.net/Cartoons/BabyBlues/OnTheRemote.gif

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