Posted by Richard Crowley on 01/11/45 11:46

"Larry, Darryl and Darryl" wrote ...
>I need to calculate the dimensions of a 1/3" 16:9 CCD. This is so I
>can
> do accurate Field-Of-View comparisons and tests in various 3D
> software.
>
> The FOV calculation is easy, but how do I calculate the dimensions of
> the
> chip? I need precision, since a millimeter can mean a complete
> misalignment later.

Seems like simple trig if you are assuming that the diagonal
(the hypotenuse of the triangle) is actually "1/3 of an inch".

Otherwise, it is not something you can "calculate", you must
get the actual image area dimensions from the manufacturer.

"1/3 of an inch" is a nominal size (to distinguish it from the
1/2 and 2/3 and 1/4 inch series.

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