Posted by Richard Crowley on 05/03/06 04:46

"Larry in AZ" <usenet2@DE.LETE.THISljvideo.com> wrote in message
news:Xns97B76C268EBF6thefrogprince@70.169.32.36...
> Waiving the right to remain silent, "Richard Crowley"
> <rcrowley@xpr7t.net>
> said:
>
>> "Larry, Darryl and Darryl" wrote ...
>>>I need to calculate the dimensions of a 1/3" 16:9 CCD. This is so I
>>>can
>>> do accurate Field-Of-View comparisons and tests in various 3D
>>> software.
>>>
>>> The FOV calculation is easy, but how do I calculate the dimensions
>>> of
>>> the chip? I need precision, since a millimeter can mean a complete
>>> misalignment later.
>>
>> Seems like simple trig if you are assuming that the diagonal
>> (the hypotenuse of the triangle) is actually "1/3 of an inch".
>
> IIRC, chip sizes are measured on the horizontal dimension.

My understanding is that they are measured diagonally
because that is what is necessary to cover the max circle
that the lens must image.

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