|
|
Posted by fred-bloggs on 04/21/06 13:58
"Nicolas Tade" <NGinterest@gmx.net> wrote in
news:4aru2qFul0spU1@individual.net:
> Hi,
>
> I am trying to calculate the file size of a recorded wav-file in
> mp3-format. I know I can just multiply the total number of seconds
> with 128 Kbit/s. But how do all the other factors fit in here, e.g.
> 44,100 KHz, 2 channel stereo, ...?
> Is 128 Kbit/s actually composed of 44,100 KHz and 2 channels? I guess
> I could also use 128 Kbit/s with 22 KHz, and the file size would be
> smaller. So how can I calculate that with 22 KHz?
>
The number of channels and the sampling frequency are irrelevant.
The size in kbytes is 16 x duration in seconds.
--
fred
Navigation:
[Reply to this message]
|